If f and g are real functions defined by f (x) = x2 + 7 and g (x) = 3x + 5, find each of the following
f (3) + g (– 5)
Given: f and g are real functions such that f (x) = x2 + 7 and g (x) = 3x + 5
To find: f (3) + g (– 5)
Explanation: the given
f (x) = x2 + 7
Now putting x = 3 in above function, we get
f (3) = 32 + 7 = 9 + 7 = 16……..(i)
and also given
g (x) = 3x + 5
Now putting x = -5 in above function, we get
g (-5) = 3(-5) + 5 = -15 + 5 = -10…………(ii)
Adding equation (i) and (ii), we get
f (3) + g (– 5) = 16-10 = 6
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