Q2 of 45 Page 43

Solve the following examples.

In ∆ PQR; PQ = 8 , QR = , PR = Is ∆ PQR a right angled triangle? If yes, which angle is of 90°?


As,


(√5)2 + (√3)2 = (√8)2


⇒ QR2 + PR2 = PQ2


i.e. sides of the triangle ABC satisfy the Pythagoras theorem


(Hypotenuse)2 = (base)2 + (Perpendicular)2


∴ PQR is a right-angled triangle at R [As hypotenuse is PQ].


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