Q5 of 45 Page 38

For finding AB and BC with the help of information given in figure 2.20, complete following activity.


In ∆ABC, ∠ABC = 900


So AB2 + BC2 = AC2


⇒ 2AB2 = 5


⇒ AB2 =


⇒ AB = √ = X(Say)


AB = BC = √


∠BAC = 450 Since AB = BC


NOW √ = X√5


X =


Similarly, X2√2 = √


X =


Similarly, X√8 = √


X =


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