In the figure 2.22, M is themidpoint of QR. ∠PRQ = 90°. Prove that, PQ2 = 4PM2 – 3PR2

In ∆PRQ, ∠PRQ = 900
PQ2 = PR2 + QR2 – – – 1
In ∆PRM, ∠PRM = 900
PM2 = PR2 + MR2
⇒ PM2 = PR2 +
2 [ M is midpoint]
⇒ 4(PM2 – PR2) = QR2 – – – 2
1 And 2 implies
PQ2 = PR2 + 4(PM2 – PR2)
⇒ PQ2 = 4PM2 – 3PR2
PROVED.
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