Q4 of 45 Page 38

See figure 2.19. Find RP and PSusing the information given in ΔPSR.


Ans. RP = 12, PS = 6

In ∆PSR, ∠PSR = 900


So PS2 + SR2 = RP2


⇒ 62 + (RPcos(300))2 = RP2


⇒ 62 + RP2 = RP2


⇒ 62 =


⇒ RP2 = 4×36


Thus RP = 12.


PS = RPcos(300)


⇒ PS = 12×


PS = 6√3.


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