Differentiate

(v) (uv)′ = u′v + uv′ (Leibnitz or product rule)

Let us take u = () and v = ()

Applying Product rule

(gh)′ = g′h + gh′

Taking g = e^x and h = sinx

= e^xsinx + e^xcosx

u’ = e^xsinx + e^xcosx

Putting the above obtained values in the formula:-