Differentiate

(iv) (uv)′ = u′v + uv′ (Leibnitz or product rule)

Let us take u = e^x(x-1) and v = (x+1)

Applying Product rule

(gh)′ = g′h + gh′

Taking g = and h = x – 1

[e^x(x-1)]’ = e^x(x-1) + e^x (1)

= e^x(x-1) + e^x

u’ = e^xx

Putting the above obtained values in the formula:-