Differentiate the following with respect to x:
(ax2 + bx + c)
To Find: Differentiation
NOTE : When 2 functions are in the product then we used product rule i.e ![]()
Formula used:
(yn) = nyn - 1![]()
Let us take y= (ax2 + bx + c)
So, by using the above formula, we have
(ax2 + bx + c) = 2ax + b
Differentiation of y = (ax2 + bx + c) is 2ax + b
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