Show that ƒ(x) =
is continuous at each point except 0.
Given function is ƒ(x) = ![]()
Left hand limit at x = 0
= 0
Right hand limit at x = 0
= 0
Also,
f(0) = 1
As,
![]()
f(x) = x for other values of x expect 0 f(x) = 1,2,3,4…
Therefore,
f(x) is not continuous everywhere expect at x = 0
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