Prove that the function ƒ given ƒ(x)=|x-3|, x є R is continuous but not differentiable at x=3
f(x)=|x-3|
Since every modulus function is continuous for all real x, f(x) is continuous at x=3.
f(x) = ![]()
To prove differentiable , we will use the following formula.
=
= f(a)
L.H.L ![]()
= ![]()
= ![]()
= 1
R.H.L: ![]()
= ![]()
= ![]()
= -1
Since, L.H.L
R.H.L, f(x) is not differentiable at x=5.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.



