Prove that
ƒ(x) =
is discontinuous at x=0
LHL:
=![]()
=![]()
=2 ![]()
= 2 x ![]()
= ![]()
RHL:
=![]()
=![]()
=2 ![]()
= 2 x ![]()
= ![]()
f(0)= 1
Since,
f(0)
f is discontinuous at x=0.
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