Locate the point of discontinuity of the function
ƒ(x) = 
Given function f(x) = ![]()
Left hand limit at x = 1:
![]()
![]()
![]()
= 1 – 1 + 2 – 2
= 0
Right hand limit at x = 1:
![]()
![]()
![]()
= 1 – 1 + 2 – 2
= 0
Also, f(1) = 4
As we can see that,
![]()
Therefore,
f(x) is not continuous at x = 1
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