Prove that
ƒ(x) =
is continuous at x=2
LHL:
=![]()
= 1
RHL:
=![]()
= 1
f(x)=2x-3 [this equation is taken as equality for x=1 lies there]
f(2)= 1
Since,
= f(2)
f is continuous at x=2.
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