Show that function
ƒ(x) =
is continuous but not differentiable at x=1
Given function f(x) = ![]()
Left hand limit at x = 1:
![]()
Right hand limit at x = 1:
![]()
Also, f(1) = 12 – 1 = 0
As,
![]()
Therefore,
f(x) is continuous at x = 1
Now, let’s see the differentiability of f(x):
LHD at x = 2:
![]()
![]()
RHD at x = 2:
![]()
= 2 + 2 = 4
As, LHD ≠ RHD
Therefore,
f(x) is not differentiable at x = 2
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