Q9 of 99 Page 33

If the mean and variance of a binomial distribution are 4 and 3 respectively, find the probability of no-success.

Given:


Mean=4


Variance=3


P(x=0)=?


P(x=r)= nCr pr qn-r


p(x=0)= 11qn


4(1-p)=3



=q



np=4


n=16



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