Q7 of 99 Page 33

The mean of a binomial distribution is 20, and the standard deviation 4. Calculate the parameters of the binomial distribution.

Standard deviation =


⇒ npq = 16


Therefore, np = 20, npq = 16


Let X denote the variance with parameters n and p


p + q = 1 ⇒ q = 1 - p


mean = np = 20 and variance = npq = 16


npq = 16


⇒20 q = 16





Now, np = 20



⇒ n = 100



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