Q12 of 99 Page 33

Mark the correct alternative in the following:

If the mean and variance of a binomial variate X are 2 and 1 respectively, then the probability that X takes a value greater than 1 is


Given:


Mean= 2


Variance=1


P(x>1)=?


P(x>1)=1-p(x1)


= 1-[p(x=0)+p(x=1)]


=1-[ 11qn +npqn-1]


2(1-p)=1



=q



np=2


n=4



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