Q5 of 99 Page 33

Determine the binomial distribution whose mean is 20 and variance 16.

Let X denote the variance with parameters n and p


p + q = 1 ⇒ q = 1 - p


Given, mean = np = 20 and variance = npq = 16


npq = 16


⇒20q = 16





Now, np = 20



⇒ n = 100


∴ n = 100 and


The required binomial distribution is given by,



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