Q11 of 99 Page 33

The mean and variance of binomial variate with parameters n and p are 16 and 8 respectively. Find P (X = 0), P (X = 1) and P (X ≥ 2).

Given that parameters for binomial distribution are n, p








Now, np = 16



⇒ n = 32



The required binomial distribution is given by,








P(X≥2) = 1 - [P(X = 0) + P(X = 1)]





So,



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