Choose the correct answer.
Let f(x) = |x| and g(x) = |x3|, then
Given f(x) = |x| and g(x) = |x3|,
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Checking differentiability and continuity,
LHL at x =0,
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RHL at x =0,
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And f(0)=0
Hence, f(x) is continuous at x =0.
LHD at x =0,
![]()
![]()
RHD at x =0,
![]()
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∵ LHD ≠RHD
∴ f(x) is not differentiable at x =0.
![]()
Checking differentiability and continuity,
LHL at x =0,
![]()
RHL at x =0,
![]()
And g(0)=0
Hence, g(x) is continuous at x =0.
LHD at x =0,
![]()
![]()
RHD at x =0,
![]()
![]()
∵ LHD = RHD
∴ g(x) is differentiable at x =0.
Hence, option A is correct.
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