Show that the function F(x) =
is
Neither continuous and nor differentiable, if m≤0.
LHL = ![]()
= ![]()
= ![]()
= Not defined, as m
0
RHL = ![]()
= ![]()
= ![]()
= Not Defined, as ![]()
Since, LHL and RHL are not Defined ,So f(x) is not continuous.
Let x = 0 for ![]()
Now,
(LHD at x = 0) = ![]()
= ![]()
= ![]()
= ![]()
= ![]()
= ![]()
= Not Defined , as ![]()
(RHD at x = 0) = ![]()
= ![]()
= ![]()
= ![]()
= Not Defined , as ![]()
Hence, f(x) is not differentiable at x = 0 for ![]()
Couldn't generate an explanation.
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