Show that the function f defined as follows,

Is continuous at x = 2, but not differentiable there at x = 2.
For continuity,
LHl(at x = 2) = RHL (at x = 2)
f(2) = 2(2)2 - 2
= 8 - 2 = 6
LHL = ![]()
= ![]()
= ![]()
= 8 - 2
= 6
RHL = ![]()
= ![]()
= ![]()
= 6
Since, LHL = RHL = f(2)
Hence, F(x) is continuous at x = 2
For differentiability,
LHD(at x = 2) = RHD (at x = 2)
(LHD at x = 2) = ![]()
= ![]()
= ![]()
= ![]()
= ![]()
= ![]()
= ![]()
= 6
(RHD at x = 2) = ![]()
= ![]()
= ![]()
= ![]()
= 5
Since, (RHD at x = 2)
(LHD at x = 2)
Hence, f(2) is not differentiable at x = 2.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.

