Show that the function F(x) =
is
Differentiable at x = 0, if m > 1.
f(x) = 
(LHD at x = 0) = ![]()
= ![]()
= ![]()
= ![]()
= ![]()
= ![]()
= 0 * k [when - 1
]
(RHD at x = 0) = ![]()
= ![]()
= ![]()
=
= 0
Since, (LHD at x = 0) = (RHD at x = 0)
Hence, f(x) is differentiable at x = 0
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