Show that the function F(x) =
is
Continuous but not differentiable at x = 0, if 0<m<1.
LHL = ![]()
= ![]()
= ![]()
= ![]()
= 0 x k [when
]
= 0
RHL = ![]()
= ![]()
= ![]()
= ![]()
= 0 x k [when
]
= 0
LHL = RHL = f(0)
Since, f(x) is continuous at x = 0
For Differentiability at x = 0
(LHD at x = 0) = ![]()
= ![]()
= ![]()
= ![]()
= Not Defined [since 0<m<1]
(RHD at x = 0) = ![]()
= ![]()
= ![]()
= ![]()
= 0
Since , (LHD at x = 0)
(RHD at x = 0)
Hence, f(x) is continuous at x = 0 but not differentiable.
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