Show that f(x) = |x - 3| is continuous but not differentiable at x = 3.
f(x) = |x – 3|
Therefore we can write it as,
![]()
f(3) = 3 - 3 = 0
LHL = ![]()
= ![]()
= ![]()
= ![]()
RHL = ![]()
= ![]()
= ![]()
= 0
LHL = RHL = f(3)
Since, f(x) is continuous at x = 3
(LHD at x = 3) = ![]()
= ![]()
= ![]()
= ![]()
= - 1
(RHD at x = 3) = ![]()
= ![]()
= ![]()
= ![]()
= 1
(LHD at x = 3)
(RHD at x = 3)
Hence, f(x) is continuous but not differentiable at x = 3.
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