i)![]()
⇒![]()
Now, we know that 1-cos2x=2sin2x
So, applying this identity in the given integral, we get,
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⇒![]()
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Ans: ![]()
ii)![]()
⇒![]()
Now, we know that 1+cos2x=2cos2x
So, applying this identity in the given integral, we get,
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⇒![]()
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Ans: ![]()
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