Q3 of 380 Page 658

Evaluate the following integrals:

(i)


(ii)


i)


⇒


Now, we know that 1-cos2nx=2sin2nx


So, applying this identity in the given integral, we get,



⇒




Ans:


(ii)


We know that 1-cos2x=sin2x


⇒


⇒Put cosx=t


⇒-sinxdx=dt


⇒


⇒


⇒


⇒


Resubstituting the value of t=cosx we get,


⇒


Ans:


More from this chapter

All 380 →
1

Evaluate the following integrals:

(i)


(ii)


2

Evaluate the following integrals:

(i)


(ii)


4

Evaluate the following integrals:


 5

Evaluate the following integrals: