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Q5 of 380 Page 658

Evaluate the following integrals:

⇒

Substitute 2x-3=u

⇒ 2dx=du

⇒dx=du/2

⇒

⇒ We know that 1-cos²x=sin²x

⇒

⇒Put cosu=t

⇒-sinxdu=dt

⇒

⇒

⇒

⇒

⇒

Resubstituting the value of t=cosu and u=2x-3 we get

⇒

⇒

Now as we know cos(-x)=cosx

⇒

=

Ans:

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