Evaluate the following integrals:
(i) ![]()
(ii) ![]()
i) ![]()
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1-cosx=2sin2x/2 and 1+cosx=2cos2x/2
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Now sec2(x/2)-1=tan2(x/2)
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⇒2tan(x/2)-x+c
Ans: 2tan(x/2)-x+c
(ii) ![]()
⇒![]()
1-cosx=2sin2x/2 and 1+cosx=2cos2x/2
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Now cosec2 (x/2)-1=cot2 (x/2)
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⇒-2cot(x/2)-x+c
Ans: ⇒-2cot(x/2)-x+c
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