Evaluate the following integrals:
(i) 
(ii) 
(i) 
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1-cos2x=2sin2x and 1+cos2x=2cos2x
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Now sec2x-1=tan2x
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⇒tanx-x+c
Ans: tanx-x+c
(ii) 
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1-cos2x=2sin2x and 1+cos2x=2cos2x
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Now cosec2x-1=cot2x
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⇒-cotx-x+c
Ans: -cotx-x+c
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