Q4 of 380 Page 658

Evaluate the following integrals:


Substitute 3x+5=u


⇒3dx=du


⇒dx=du/3


⇒


Now We know that 1-cos2x=sin2x ,


⇒


⇒Substitute sinu=t


⇒cosu du=dt


⇒


⇒


⇒


⇒


Resubstituting the value of t=sinu and u=3x+5 we get,


⇒


Ans:


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