Q3 of 181 Page 1196

Find the distance of the point (3, 4, 5) from the plane


Formula :


where () is point from which distance is to be calculated


Therefore ,


Plane can be written in cartesian form as


2x - 5y + 3z = 13


2x - 5y + 3z - 13 = 0


Point = ( 3 , 4 , 5 )


Distance





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5

Find the distance of the point (2, 1, 0) from the plane 2x + y + 2z + 5 = 0.