Find the vector and Cartesian equations of a plane containing the two lines
and
Also show that the lines
lies in the plane.
Given : Equations of lines -
![]()
![]()
To Prove :
are coplanar.
To Find : Equation of plane.
Formulae :
1) Cross Product :
If
are two vectors
![]()
![]()
then,

2) Dot Product :
If
are two vectors
![]()
![]()
then,
![]()
3) Coplanarity of two lines :
If two lines
are coplanar then
![]()
4) Equation of plane :
If two lines
are coplanar then equation of the plane containing them is
![]()
Where,
![]()
Answer :
Given equations of lines are
![]()
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Let, ![]()
Where,
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Now,

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Therefore,
![]()
= 40 + 10 + 24
= 74
……… eq(1)
And
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= 60 + 30 – 16
= 74
……… eq(2)
From eq(1) and eq(2)
![]()
Hence lines
are coplanar.
Equation of plane containing lines
is
![]()
Now,
![]()
From eq(1)
4
Therefore, equation of required plane is
![]()
![]()
![]()
This vector equation of plane.
As ![]()
![]()
= 20x + 10y – 8z
Therefore, equation of plane is
20x + 10y – 8z = 74
20x + 10y – 8z – 74 = 0
10x + 5y – 4z – 37 = 0
This Cartesian equation of plane.
Couldn't generate an explanation.
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