Q4 of 181 Page 1196

Find the distance of the point (1, 1, 2) from the plane


Formula :


where () is point from which distance is to be calculated


Therefore ,


Plane can be written in cartesian form as


2x - 2y + 4z + 5 = 0


Point = ( 1 , 1 , 2 )


Distance





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Find the distance of the point from the plane

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Find the distance of the point (3, 4, 5) from the plane

5

Find the distance of the point (2, 1, 0) from the plane 2x + y + 2z + 5 = 0.

 6

Find the distance of the point (2, 1, - 1) from the plane x – 2y + 4z = 9.