Find the vector and Cartesian equations of the plane passing through the origin and parallel to the vectors
and ![]()
Given -
&
are two lines to which a plane is parallel and it passes through the origin.
To find – The equation of the plane
Tip – A plane parallel to two vectors will have its normal in a direction perpendicular to both the vectors, which can be evaluated by taking their cross product
![]()

![]()
![]()
The plane passes through origin (0, 0, 0).
Formula to be used – If a line passes through the point (a, b, c) and has the direction ratios as (a’, b’, c’), then its vector equation is given by
where λ is any scalar constant
The required plane will be
![]()
![]()
The vector equation : ![]()
The Cartesian equation : x + 2y + 3z = 0
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.
