Q9 of 181 Page 1198

Find the distance between the planes x + 2y + 3z + 7 = 0 and 2x + 4y + 6z + 7 = 0.

Formula : The distance between two parallel planes, say


Plane 1:ax + by + cz + d1 = 0 &


Plane 2:ax + by + cz + d2 = 0 is given by the formula



where () are constants of the planes


Therefore ,


First Plane x + 2y + 3z + 7 = 0


2(x + 2y + 3z + 7) = 0


2x + 4y + 6z + 14 = 0 …… (1)


Second plane 2x + 4y + 6z + 7 = 0 …… (2)


Using equation (1) and (2)


Distance between both planes





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