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28. The Plane
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Q8 of 181 Page 1181

Find the vector equation of a plane whose Cartesian equation is 5x - 7y + 2z + 4 = 0.

Given :


Cartesian equation of the plane is


5x – 7y + 2z + 4 = 0


To Find : Vector equation of the given plane.


Formulae :


1) Dot Product :


If are two vectors




then,



Given the equation of the plane is


5x – 7y + 2z + 4 = 0


⇒ 5x – 7y + 2z = - 4


The term (5x – 7y + 2z) can be written as



But



Therefore the equation of the plane is



or



This is Vector equation of the given plane.


More from this chapter

All 181 →
6

Find the length of the perpendicular from the origin to the plane Also write the unit normal vector from the origin to the plane.

7

Find the Cartesian equation of the plane whose vector equation is

9

Find a unit vector normal to the plane
x – 2y + 2z = 6.

10

Find the direction cosines of the normal to the plane 3x – 6y + 2z = 7.

Questions · 181
28. The Plane
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