In each of the following, using the remainder theorem, find the remainder when f(x) is divided by g(x):
f(x) = 9x3-3x2+x-5, g(x) = x=
We have,
f(x) = 9x3-3x2+x-5 and g(x) = x=
Therefore, by remainder theorem when f (x) is divided by g (x) = x - 
, the remainder is equal to f (
)
Now, f(x) = 9x3-3x2+x-5
f (
) = 9 (
)3 – 3 (
)2 + 
– 5
= (9 * 
) – (3 * 
) + 
– 5
= 
- 
+ 
– 5
= 2 – 5 = -3
Hence, the required remainder is -3.
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