If x3+6x2+4x+k is exactly divisible by x+2, then k =

Q2 of 96 Page 6

If x³+6x²+4x+k is exactly divisible by x+2, then k =

Since, x+2 is exactly divisible by f(x)

Means x+2 is a factor of f (x), so

f (-2) = 0

(-2)³ + 6 (-2)² +4 (-2) + k = 0

-16 + 24 + k = 0

k= - 8

If f(x) =x⁴-2x³+3x²-ax-b when divided by x-1, the remainder is 6, then find the value of a + b

If x-2 is factor of x²-3ax-2a, then a =

If x-a is a factor of x³-3x²a+2a²x+b, then the value of b is

If x¹⁴⁰+2x¹⁵¹ +k is divisible by x+1, then the value of k is