Q14 of 96 Page 6

If (3x-1)7 =a7x7+a6x6+a5x5+….a1x+a0, then a7+a6+a5+….+a1+a0=

We have,

(3x – 1)7 = a7x7+a6x6+a5x5+….a1x+a0


Putting x = 1, we get


(3 * 1 – 1)7 = a7 + a6 + a5 + a4 + a3 + a2 + a1 + a0


(2)7 = a7 + a6 + a5 + a4 + a3 + a2 + a1 + a0


a7+a6+a5+….+a1+a0 = 128

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