Q3 of 38 Page 190

Let’s find a number such that one-fourth of the number is 1 less than one-third of the number.

Let a number be x

Now according to the given criteria,


one-fourth of the number = …..(i)


1 less than one-third of the number = …….(ii)


So from question equation (i) and equation (ii) are equal,


Hence




By cross multiplying we get


⇒ 3x=4(x-3)


⇒ 3x=4x-12


⇒ 12=4x-3x


⇒ x=12


Hence the number is 12


More from this chapter

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1

Sima has written a number. If 2 is added to twice the number, it becomes 5 less than thrice the number. Let’s write the numbers that Sima has written.

 2

Let’s write down three consecutive integers such that 5 less than the sum of the number is equal to 11 more than twice the second number. Let’s find the three consecutive integers.

 4

Let’s find a fraction whose denominator is 2 more than the numerator and when 3 is added to the numerator and 3 subtracted from the denominator, the fraction becomes equal to .

 5

Sucheta wrote a fraction whose denominator is 3 more than the numerator. Again she added 2 to the numerator and subtracted 1 from the denominator and also subtracted 1 from the numerator and added 2 with the denominator she will get two fraction whose product is . Let’s write the fraction written by Sucheta.