Q15 N of 38 Page 190

Let’s find the roots of the equations (i.e. let’s solve the equations).

LCM of 14 and 7 is 14, and LCM of 28 and 4 is 28, so the above equation becomes

By cross multiplying we get

2(25x-9)=18x+46

⇒ 50x-18=18x+46

⇒ 50x-18x=46+18

⇒ 32x=64

This is the required root of the given equation.

15 L

Let’s find the roots of the equations (i.e. let’s solve the equations).

15 M

Let’s find the roots of the equations (i.e. let’s solve the equations).

15 O

Let’s find the roots of the equations (i.e. let’s solve the equations).

5x - (4x-7) (3x-5) = 6-3 (4x-9) (x-1)