Q4 of 38 Page 190

Let’s find a fraction whose denominator is 2 more than the numerator and when 3 is added to the numerator and 3 subtracted from the denominator, the fraction becomes equal to .

Let the numerator of a fraction be x

Then given the denominator of the fraction is 2 more than the numerator, so the denominator = x+2


So the fraction is …..(i)


Now according to the given criteria,


when 3 is added to the numerator and 3 subtracted from the denominator = …..(ii)


So from question equation (ii) is equal to ,


Hence



By cross multiplying we get


3(x+3)=7(x-1)


3x+9=7x-7


9+7=7x-3x


4x=16



From equation (i), the fraction is



Hence the fraction is


More from this chapter

All 38 →