Let’s find a fraction whose denominator is 2 more than the numerator and when 3 is added to the numerator and 3 subtracted from the denominator, the fraction becomes equal to
.
Let the numerator of a fraction be x
Then given the denominator of the fraction is 2 more than the numerator, so the denominator = x+2
So the fraction is
…..(i)
Now according to the given criteria,
when 3 is added to the numerator and 3 subtracted from the denominator =
…..(ii)
So from question equation (ii) is equal to
,
Hence
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By cross multiplying we get
⇒ 3(x+3)=7(x-1)
⇒ 3x+9=7x-7
⇒ 9+7=7x-3x
⇒ 4x=16
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From equation (i), the fraction is
![]()
Hence the fraction is ![]()
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