Let’s find the roots of the equations (i.e. let’s solve the equations).
3(y-5)2 + 5y = (2y-3)2 +1
3(y-5)2 + 5y = (2y-3)2 –(y+1)2+1
⇒ 3(y2 + 25 – 10y)+ 5y = (4y2 + 9 – 12y)- (y2+1+2y)+1
⇒3 y2 + 75 – 30 y + 5y= 4y2 + 9 – 12y - y2 – 1-2y+1
⇒3 y2 + 75 – 25 y = 3y2 + 9 – 14y
⇒3 y2 - 3y2 +75 – 9 = -14 y + 25y
⇒66 = 11y
Y = 6
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.