Q15 of 38 Page 190

Let’s find the roots of the equations (i.e. let’s solve the equations).

3(y-5)2 + 5y = (2y-3)2 +1


3(y-5)2 + 5y = (2y-3)2 –(y+1)2+1

3(y2 + 25 – 10y)+ 5y = (4y2 + 9 – 12y)- (y2+1+2y)+1


3 y2 + 75 – 30 y + 5y= 4y2 + 9 – 12y - y2 – 1-2y+1


3 y2 + 75 – 25 y = 3y2 + 9 – 14y


3 y2 - 3y2 +75 – 9 = -14 y + 25y


66 = 11y


Y = 6


More from this chapter

All 38 →