Q8 of 38 Page 190

Divide 830 into two parts in such a way, that 30% if one part will be 4 more than 40% of the other.

Let the two parts be x and y such that

x+y=830…..(i)


So y=830-x


So the two parts will be x and (830-x)


Now according to the given criteria,


30% of x=40% of (830-x) +4





⇒ 3x=4(830-x)+40


⇒ 3x=3320-4x+40


⇒ 3x+4x=3360


⇒ 7x=3360



So the other part is 830-x=830-480=350


Hence the two parts are 480 and 350.


More from this chapter

All 38 →
6

Raju wrote a number having 2 digit where the digit in the ten’s position is thrice the digit in the unit position and the new number obtained by reversing the positions of the digits is 36 less than the initial number. Let’s find the number writer by Raju.

 7

If the sum of two numbers is 89 and their difference is 15, let’s find the two numbers.

 9

Divide 56 into parts, so that thrice of the first part becomes 48 more than one third of the second part.

 10

part of a pole lies in mud, part lies in water and the remaining 5 meters lies above the water. Let’s find the length of the pole and write it.