Q15 of 38 Page 190

Let’s find the roots of the equations (i.e. let’s solve the equations).

5x - (4x-7) (3x-5) = 6-3 (4x-9) (x-1)


5x - (4x-7) (3x-5) = 6-3 (4x-9) (x-1)


⇒ 5x-(4x(3x-5)-7(3x-5))=6-3(4x(x-1)-9(x-1))


⇒ 5x-(12x2-20x-21x+35)=6-3(4x2-4x-9x+9)


⇒ 5x-(12x2-41x+35)=6-3(4x2-13x+9)


⇒ 5x-12x2+41x-35=6-12x2+39x-27


⇒ 46x-39x=35+6-27


⇒ 7x=14



=2


This is the required root of the given equation.


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