Q3 of 115 Page 8

In Fig 8.107, AB ||CD ||EF and GH ||KL. Find ∠HKL.

Produce LK to meet GF at N

Now,


∠CHG = ∠HGN = 60o(Alternate angle)


∠HGN = ∠KNF = 60o(Corresponding angles)


Therefore,


∠KNG = 120o


∠GNK = ∠AKL = 120o(Corresponding angle)


∠AKH = ∠KHD = 25o(Alternate angles)


Therefore,


∠HKL = ∠AKH + ∠AKL


= 25o + 120o


= 145o


More from this chapter

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