Q25 of 115 Page 8

In Fig. 8.137, if AB|| HF and DE||FG, then the measure of ∠FDE is

Given that,

AB ‖ HF and CD cuts them


∠HFC = ∠FDA (Corresponding angle)


∠FDA = 28o


∠FDA + ∠FDE + ∠EDB = 180o (Linear pair)


28o + ∠FDE + 72o = 180o


∠FDE = 80o

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