In Fig. 8.136, if CP || DQ, then the measure of x is

Given that,
CP ‖ BQ
Produce CP to E
So, PE ‖ BQ and AB cuts them
∠QBE = ∠CBA = 105o (Corresponding angles)
In ![]()
∠CEA + ∠ECA + ∠EAC = 180o
105o + ∠ECA + 25o = 180o
∠ECA = 50o
∠PCA + ∠ECA = 180o (Linear pair)
x + 50o = 180o
x = 130o
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