A solution is prepared by dissolved 10 g of non-volatile solute in 200 g of water. It has a vapour pressure of 31.84 mm Hg at 308 K. Calculate the molar mass of the solute.
(Vapour pressure of pure water at 308 K = 32 mm Hg).
According to Raoult’s law, 
Where PO→ Vapour pressure of pure water
P → Vapour pressure of solution
w → Weight of solute
m → Molecular weight of solute
W → Weight of solvent
M → Molecular weight of solvent
Thus, 
Or, 0.005 m = 0.9 or, m = 180
Thus molar mass of the solute 180 gm./mol
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